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OpenStudy (learningallday):
OpenStudy (learningallday):
Solve for x. Express the answer in simplest form.
OpenStudy (learningallday):
\[\frac{ 2 }{ 1 =\frac{ 8x }{ ? }}\]
OpenStudy (learningallday):
will fan in medal
OpenStudy (australia.j.):
trying now
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OpenStudy (australia.j.):
is this multiple choice
OpenStudy (australia.j.):
hello???
OpenStudy (learningallday):
no
OpenStudy (australia.j.):
okay well i got 3
OpenStudy (australia.j.):
wait a second let me do some thing
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OpenStudy (learningallday):
\[\frac{ 3 }{ ? }\]
OpenStudy (australia.j.):
nope just 3
OpenStudy (learningallday):
theres is more nubers to that its a fraction
OpenStudy (australia.j.):
wait s minute
OpenStudy (australia.j.):
nope still getting 3. do you have notes. if so show me
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OpenStudy (learningallday):
Solve for x. Express the answer in simplest form.
OpenStudy (australia.j.):
dang this is hard
OpenStudy (learningallday):
Solve for a variable in a proportion.
OpenStudy (learningallday):
@mathmate
OpenStudy (learningallday):
to help both of us out
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OpenStudy (australia.j.):
you have two equations on here. which one do i use. In simplest form it's 3
OpenStudy (australia.j.):
helloooooo???
OpenStudy (mathmate):
I'll be glad to offer an example and steps.
OpenStudy (learningallday):
OpenStudy (australia.j.):
please do cause his/her question is confusing
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OpenStudy (australia.j.):
@learningallday you still there
OpenStudy (learningallday):
yup
OpenStudy (australia.j.):
@mathmate what you doing lad
OpenStudy (mathmate):
Solve
\(\Large \frac{2x+3}{5}=\frac{4x-3}{3}\)
First we cross multiply to get:
\(\Large 3(2x+3)=5(4x-3)\)
then we multiply out each side:
\(\Large 6x+9=20x-15\)
next we transpose and isolate the unknown
\(\Large 6x-20x=-15-9\)
Simplify each side:
\(\Large -14x = -24\)
Finally solve for x:
\(\Large x=(-24)/(-14)=\frac{12}{7}\)
Next is to substitute x=12/7 into the original equation and show that both sides are equal.
OpenStudy (australia.j.):
i gave @learningallday a medal for trying
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OpenStudy (australia.j.):
and for giving me one
OpenStudy (learningallday):
hello mate
OpenStudy (mathmate):
Would you like to attempt the original question and post your answer for a check?
@learningallday @Australia.J.