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Mathematics 13 Online
OpenStudy (learningallday):

can i get some help

OpenStudy (learningallday):

OpenStudy (learningallday):

Solve for x. Express the answer in simplest form.

OpenStudy (learningallday):

\[\frac{ 2 }{ 1 =\frac{ 8x }{ ? }}\]

OpenStudy (learningallday):

will fan in medal

OpenStudy (australia.j.):

trying now

OpenStudy (australia.j.):

is this multiple choice

OpenStudy (australia.j.):

hello???

OpenStudy (learningallday):

no

OpenStudy (australia.j.):

okay well i got 3

OpenStudy (australia.j.):

wait a second let me do some thing

OpenStudy (learningallday):

\[\frac{ 3 }{ ? }\]

OpenStudy (australia.j.):

nope just 3

OpenStudy (learningallday):

theres is more nubers to that its a fraction

OpenStudy (australia.j.):

wait s minute

OpenStudy (australia.j.):

nope still getting 3. do you have notes. if so show me

OpenStudy (learningallday):

Solve for x. Express the answer in simplest form.

OpenStudy (australia.j.):

dang this is hard

OpenStudy (learningallday):

Solve for a variable in a proportion.

OpenStudy (learningallday):

@mathmate

OpenStudy (learningallday):

to help both of us out

OpenStudy (australia.j.):

you have two equations on here. which one do i use. In simplest form it's 3

OpenStudy (australia.j.):

helloooooo???

OpenStudy (mathmate):

I'll be glad to offer an example and steps.

OpenStudy (learningallday):

OpenStudy (australia.j.):

please do cause his/her question is confusing

OpenStudy (australia.j.):

@learningallday you still there

OpenStudy (learningallday):

yup

OpenStudy (australia.j.):

@mathmate what you doing lad

OpenStudy (mathmate):

Solve \(\Large \frac{2x+3}{5}=\frac{4x-3}{3}\) First we cross multiply to get: \(\Large 3(2x+3)=5(4x-3)\) then we multiply out each side: \(\Large 6x+9=20x-15\) next we transpose and isolate the unknown \(\Large 6x-20x=-15-9\) Simplify each side: \(\Large -14x = -24\) Finally solve for x: \(\Large x=(-24)/(-14)=\frac{12}{7}\) Next is to substitute x=12/7 into the original equation and show that both sides are equal.

OpenStudy (australia.j.):

i gave @learningallday a medal for trying

OpenStudy (australia.j.):

and for giving me one

OpenStudy (learningallday):

hello mate

OpenStudy (mathmate):

Would you like to attempt the original question and post your answer for a check? @learningallday @Australia.J.

OpenStudy (learningallday):

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