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What is the equation of the quadratic function with roots -10 and -8 and a vertex at (-9, -3).
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a quadratic function is a polynomial with roots \(r_1,r_2\) which can be written in the form \[P(x) = a(x-r_1)(x-r_2)\] \(a\) is a constant which can be chosen to make the quadratic pass through an arbitrary point. You want a quadratic with roots \(-10,-8\) and a vertex at \((-9,-3)\) Set \(r_1 = -10\) and \(r_2 = -8\), then put the point \((-9,-3)\) in the resulting equation and solve for the needed value of \(a\). When you have the value of \(a\), rearrange the equation into whatever form you need.
did you try what as suggested above?
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