Question

Can someone help me please??

Answer 1

lets write 4\[\sqrt{2x}\] as y
what is 4y + 6y ?

Answer 2

10y?

Answer 3

right
now replace y by 4 sqrt2x and you have ur answer

Answer 4

* 4th root of 2x
I have trouble with the equation editor!

Answer 5

I'm confused, wait so something like 10 ^ 4 sqrt 2x?

Answer 6

\[10^4\sqrt{2x}\]

Answer 7

no
its 10 * 4th root 2x

Answer 8

which option do you think it is?

Answer 9

A?

Answer 10

yes

Answer 11

Can you check another question for me?

Answer 12

ok

Answer 13

I think it's C.

Answer 14

to do this you multiply the top and bottom of the fraction by the conjugate of sqrt3+sqrt6
which is sqrt3 - sqrt 6

so we have (sqrt3 - sqrt6)(sqrt3 - sqrt6)
-----------------------
(sqrt3 - sqrt6)(sqrt3 + sqrt6)
= 3 - 2sqrt18 + 6
-------------
3 - 6

can you continue with this?

Answer 15

Wait, so was I correct?

Answer 16

hold on
lets look at this again

Answer 17

i get it
-9 - 2 sqrt18
------------
3

Answer 18

look like maybe a typo somewhere