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Mathematics 16 Online
OpenStudy (anonymous):

√2 * √800 simplify

OpenStudy (anonymous):

need to go eat dinner come on guys

OpenStudy (abdullahm):

Let's find the prime factors of 800.

OpenStudy (anonymous):

2^5 and 5^2

OpenStudy (abdullahm):

\(\Large \sqrt{2} \times \sqrt{5^2\cdot 2^5}\)

OpenStudy (anonymous):

im confused

zepdrix (zepdrix):

\[\large\rm \sqrt{2}\sqrt{800}\quad=\quad \sqrt{2\cdot 800}\quad=\quad \sqrt{2\cdot2\cdot 400}\quad=\quad \sqrt{2\cdot2\cdot4\cdot100}\]

OpenStudy (abdullahm):

we replaced 800 with 5^2 x 2^5 now we need to simply the radical sign

OpenStudy (anonymous):

hmm

OpenStudy (anonymous):

would the answer be 400

OpenStudy (anonymous):

oh its 40

zepdrix (zepdrix):

No, you didn't take square root of 100 properly :o (if you used my method hehe) it's 5^2 * 2^6 maybe that's why you guys were getting mixed up

zepdrix (zepdrix):

yay 40 c:

OpenStudy (abdullahm):

we were ignoring the sqrt 2 on the other side for the while being :p Good job c:

zepdrix (zepdrix):

o

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