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√2 * √800 simplify
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need to go eat dinner come on guys
Let's find the prime factors of 800.
2^5 and 5^2
\(\Large \sqrt{2} \times \sqrt{5^2\cdot 2^5}\)
im confused
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\[\large\rm \sqrt{2}\sqrt{800}\quad=\quad \sqrt{2\cdot 800}\quad=\quad \sqrt{2\cdot2\cdot 400}\quad=\quad \sqrt{2\cdot2\cdot4\cdot100}\]
we replaced 800 with 5^2 x 2^5 now we need to simply the radical sign
hmm
would the answer be 400
oh its 40
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No, you didn't take square root of 100 properly :o (if you used my method hehe) it's 5^2 * 2^6 maybe that's why you guys were getting mixed up
yay 40 c:
we were ignoring the sqrt 2 on the other side for the while being :p Good job c:
o
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