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Find the derivative of the function f(x) = cos^2(x) + tan^2(x)
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I got 2cos(x)sin(x) + sec2(x)
please keep in mind the the first derivative of \(\cos x\) is \(-\sin x\)
namely: \[\frac{d}{{dx}}{\left( {\cos x} \right)^2} = 2\cos x\left( {\frac{d}{{dx}}\cos x} \right) = - 2\cos x\sin x\]
ok right
:)
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I'm confused what do that tell me?
wait now im get 2tan(x)sec^2(x) - 2sin(x)cos(x)
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