OpenStudy (anonymous):

Desperate for help! I don't understand how to graph this. I'm pretty horrible at graphing. If you ever swam in a pool and your eyes began to sting and turn red, you felt the effects of an incorrect pH level. pH measures the concentration of hydronium ions and can be modeled by the function p(t) = −log10t. The variable t represents the amount of hydronium ions; p(t) gives the resulting pH level. 1.Create a graph of the pH function either by hand or using technology. Locate on your graph where the pH value is 0 and where it is 1. You may need to zoom in on your graph.

1 year ago
OpenStudy (denonakavro):

do you have a graphing calculator with you ?

1 year ago
OpenStudy (anonymous):

No but I can use the internet for one.

1 year ago
OpenStudy (denonakavro):

use this one a plug in your equation https://www.desmos.com/calculator

1 year ago
OpenStudy (anonymous):

Thank you its my go to already! c:

1 year ago
OpenStudy (anonymous):

Would I make p(t)=-log10t into f(x)=-log10x Its the same thing isnt it?

1 year ago
OpenStudy (denonakavro):

Yep same thing

1 year ago
OpenStudy (anonymous):

Wow so thats all I have to do to graph it?

1 year ago
OpenStudy (denonakavro):

"Locate on your graph where the pH value is 0 and where it is 1. You may need to zoom in on your graph."

1 year ago
OpenStudy (denonakavro):

That means it wants the point where y is equal to and y is equal to 1

1 year ago
OpenStudy (anonymous):

Would that be (1,0) and (0,2)?

1 year ago
OpenStudy (denonakavro):

give me a sec

1 year ago
OpenStudy (denonakavro):

Is Ph the P(t)

1 year ago
OpenStudy (anonymous):

Yes.

1 year ago
OpenStudy (anonymous):

@denonakavro

1 year ago
OpenStudy (denonakavro):

I believe the graph never touches those points

1 year ago
OpenStudy (anonymous):

This is what my graph looks like.. \[F(x)=\log_{10}X\]

1 year ago
OpenStudy (denonakavro):

First isnt that negative log according to your question and the ph value is 0 and 1 when y value is 1 and 0 not the x value

1 year ago
OpenStudy (anonymous):

Yes its negative.... So is this graph answering the question? On desmos I put y=0 and y=1 then circled the points.

1 year ago