Question

Do i use difference of cubes?

Factor and Solve
8x^6-y^3

Answer 1

Yesss you do :)
Recognize that the firs term can be written as a perfect cube.

Answer 2

\[\large\rm 8=2^3,\qquad\qquad x^6=x^{2\cdot3}=(x^2)^3\]

Answer 3

so would it be

(8x^2)^3-(y)^3

Answer 4

im pretty sure im wrong :p

Answer 5

Ooo close,\[\large\rm 8x^6-y^3\quad=\quad 2^3(x^2)^3-y^3\quad=\quad (2x^2)^3-y^3\]

Answer 6

Oh okay, I get it now! Thank you ;)

Answer 7

cool :)