Question

Can Someone help me and show me how to write the equation or steps to find the equation?
Two objects are moving along separate linear paths where each path is described by position, d, and time, t. The variable d is measured in meters, and the variable t is measured in seconds. The equation describing the graph of the position of the first object with respect to time is
d = 2.5t + 2.2. The graph of the position of the second object is a parallel line passing through
(t = 0, d = 1). What is the equation of the second graph?
A)d = 2.5t + 1
B)d = -0.4t + 1
C)d = 2.5t + 3.2

Answer 1

parallel means gradient is same so the constant that goes with t will be 2.5
d=2.5t + x
find the value of x by inputting t=0 d=1

Answer 2

d=2.5t+1

Answer 3

1=2.5(0)+b
b=1

Answer 4

is this right?

Answer 5

yes.
You might also remember that parallel means same slope so you know the line will be
y= 2.5x + b
b is the "y intercept" which is a fancy way to say the y value when x is 0 or in this case when t=0
in other words, they tell you t=0, d= 1: (0,1) and we see the "y-intercept" b is 1

Answer 6

thank you