Question

help @jonnyy9

Answer 1

Whats the question?

Answer 2

um

Answer 3

i m here

Answer 4

\[3+\sqrt{x+19}-\sqrt{2} when x=6\]

Answer 5

so

3 + sqrt(x+19) -sqrt2 = ? for x=6 --- yes ?

Answer 6

yes

Answer 7

substittute the 6 in place of x inside sqrt

Answer 8

can u show me how to do it the hole thing

Answer 9

yes but you need cooperate and make what i have said to you - ok. ?

Answer 10

ok

Answer 11

sqrt(x+19) = ? when x=6

Answer 12

25

Answer 13

yes nice so sqrt25 = ?

Answer 14

5

Answer 15

exactly

Answer 16

then what

Answer 17

so use this result above in your exercise - can using it there ?

Answer 18

so
3+\[\sqrt{5}-2\]

Answer 19

3 + sqrt(x+19) -sqrt2 = ? for x=6 --- yes ?

in place of sqrt(x+19) you can writing 5 - yes ?

Answer 20

yea

Answer 21

why you have wrote there sqrt5 ?

Answer 22

this is just 5 without sqrt

Answer 23

ook

Answer 24

then what
solve

Answer 25

how will be than your equation now ?

Answer 26

3+5-2

Answer 27

the answer is 6 right

Answer 28

3+5 -sqrt2 = ?

sqrt2 how you eliminate ?

Answer 29

idk um

Answer 30

sqrt2 is different term than 3 and 5 so you not can doing with nothing just assum 3 with 5 and what will get ?

Answer 31

8

Answer 32

3+5 = ?

Answer 33

yes so rewrite your equation how is now ?

Answer 34

\[8-\sqrt{2}\]

Answer 35

make it equal zero and assum to both sides sqrt2 so what will get ?

Answer 36

idk what u are saying can u show me

Answer 37

8-sqrt2 +sqrt2=0+sqrt2 - do you understand it now ?

Answer 38

ok kind of

Answer 39

so than make the calculi

Answer 40

i am still confeused

Answer 41

-sqrt2 +sqrt2 = ?

and

0 + sqrt2 = ?

Answer 42

how would i solve that

Answer 43

- 1 +1 = ?

Answer 44

1

Answer 45

right

Answer 46

no

Answer 47

o

Answer 48

yes zero

Answer 49

ok then what

Answer 50

so in the left side what will remain there ?

Answer 51

2

Answer 52

no 8

Answer 53

8-sqrt2 +sqrt2=0+sqrt2 - do you understand it now ?

yes 8 and on the right side ?

Answer 54

3

Answer 55

what is this 3 ?

Answer 56

on the right side there are 0+sqt2

Answer 57

there are 2 answers

Answer 58

there is

Answer 59

\[8\sqrt{3}\]

Answer 60

and

Answer 61

\[8-2\sqrt{3}\]

Answer 62

please answer my question

Answer 63

yea

Answer 64

so on the left side will get 8 and on the right side what will remain there ?

there are 0+sqrt2

Answer 65

yea and

Answer 66

so then what

Answer 67

ok sorry i have checked it above newly and you have got the right answer there above

8-sqrt2 will be

ok. ?

Answer 68

ok but that answeris not there

Answer 69

because you need just to calculi the value of this equation for x=6

Answer 70

3 and 2

Answer 71

so this mean that your exercise not is just what you have wrote there above - how is the text exactly ?

Answer 72

u mean theanswer

Answer 73

3+sqrt(x+19) −√2 when x=6 you have wrote there above this

Answer 74

so for x=6 you have got

this equal 8-sqrt2

yes ?

Answer 75

so would the answer be

Answer 76

yes that s all

Answer 77

\[8-2\sqrt{3}\]

Answer 78

nojust 8-sqrt2

how you get this 2sqrt3 ?

Answer 79

are you here again ?

Answer 80

its a answer

Answer 81

indifferent you have got 8-sqrt2

this is the right answer sure

Answer 82

ok. ?

Answer 83

so good luck

was my pleasure

bye

Answer 84

ok what was the answer

Answer 85

thats not there

Answer 86

bro

Answer 87

lol bro he gave you the correct answer, 8 - √2

Answer 88

by