Question

sin2x-tanx=0 , find all solutions to the equation in the interval [0,2pi)

Answer 1

Would you use the double angle identity sin2x=2sinxcosx? and change the tan to sinx/cosx

Answer 2

That might work

Answer 3

Wait if you do that wouldn't the cos be able to cancel because they both have cos in them? I might be wrong

Answer 4

Slader is telling me that you multiply the cosx and get 2sinxcos^2x-sinx=0 and then factor out a sinx

Answer 5

Oh okay

Answer 6

That makes sence

Answer 7

If you need any more help dont be afraid to asl

Answer 8

Sin2x=tanx
Sinxcosx=sinx/cosx
Cos^2x=1/2
So the values can be
π/3,2/3π, 4/3π, and 5/3π

Answer 9

Sin2x=2sinxcosx

Answer 10

Angles will be
π/4, 3/4π,5/4π and 7/4π