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Find the linear approximation of the function g(x) = (1 + x)^1/3 at a = 0.
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did you mean at x = 0?
but in short, is very simple it's just asking for the equation of tangent line at x = 0, if it's "x", not "a" the tangent line, is a LINE, thus its equation, is a LINEAR equation so, it's pretty much just asking on what is the equation of the tangent line to that graph, when x = 0 simple get the first derivative of g(x), to get the slope get g(0) to get the y-coordinate and then, just plug them all in the point-slope form y - g(0) = m(x-0)
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