write an equation for the line that is perpendicular to the given line and that passes through the given point. (12,-6); y=4x+1
do you know relation ship b/w horizontal and perpendicular line?
no
You are given the line y = 4x - 1. What is the slope of this line? \[m _{1}=?\]
4x
ok, i tell you that is\[m _{1}*m _{2}=-1\]where m1 is slope of horizontal line, and m2 is slope of perpendicular line.
To find the slope of a line perpendicular to y = 4x - 1, we take the "negative reciprocal" of \[m _{1}.\]
Please note that m is a fixed number (constant), whereas x is a variable. The slope of the given line is not 4x; it's the coefficient of x. Therefore, here, \[m _{1}=?\]
now slope of given line is\[m _{1}=4\]so, the slope of perpendicular line is\[m _{2}=-(1/4)\]
now use point slope formula\[y-y _{1}=m(x-x _{1})\]
ok
@newtonson: your comments are helpful. But do not solve the problem for 1Dfanatic; help that person find his or her own solution.
I don't understand I'M sorry...
ok i tell you in brief.
Back to basics. You are given the line y=4x-1. Compare this to y=mx+b. What is the apparent value of m, the slope?
mx would be 4x so the intercept would be 1..
@1Dfanatic : You are correct in that mx = 4x here. What is the value of the slope, m? While you can find the intercept if you wish, it's not needed here.
what do you mean by m?
As explained earlier, more than once, m represents the slope of the straight line y=mx+b. b represents the y-intercept. It's essential that you understand the meaning of m and b in the equation y=mx+b.
You are given the equation of a straight line, y=4x-1. Compare this to the general form y=mx+b. What is the value of the slope, m? What is the value of the y-intercept, b?
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Compare: y = 4x - 1 y = mx +b y=y -1=b m = ??? m is the slope of the given line.
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