If a certain rectangle has a length that is 2 Times its width, what is the ratio of the area of the rectangle to the area of an isoscrles right triangle with a hypotenuse equal to the width of the rectangle?

Question

hlambach · Answer

I keep getting 16:1, but I know that's wrong.

anonymous · Answer

Is the triangle inside the rectangle? Bc if not, the isosceles triangle could be a variety of sizes.

anonymous · Answer

nvmd, I missed the word "right"

hlambach · Answer

Yeah

anonymous · Answer

I got 8:1. Let me check first though

hlambach · Answer

That sounds right. I thought it was that, I just don't know how to get the answer.

hlambach · Answer

Can you explain what you did?

anonymous · Answer

I filled in an integer for x.

hlambach · Answer

I tried that. But what is base and height of the triangle? It's half of the hypotenuse, right?

anonymous · Answer

Bc it's a right triangle, you can apply the 45-45-90 rule (the hypotenuse is x(sqrt(2)) and legs, AKA base and height, are x)

hlambach · Answer

Not this?

hlambach · Answer

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