Question

help please

Answer 1

wht do u think should be the first step??

Answer 2

subtract 7 from both sides

Answer 3

a clue 42 = 14*3
and yeah thts correct :))

Answer 4

so then would it be \[42*3^{2-3a}=42^{-2a}\]

Answer 5

nah nah i meant
\[14\times3\times3^{2-3a} = 14\times 3^{-2a}\]

Answer 6

then would you subtract 14 from both sides

Answer 7

so now u can divide 14 on both sides u will get
\[3^{3-3a} = 3^{-2a}\]

Answer 8

@heacain girl why subtract u need to divide in this case :))

Answer 9

@heacain there???

Answer 10

im not good at algebra im not sure when to subtract of divide

Answer 11

ok :))) so now would u be able to solve it

Answer 12

see when its like x + 14 = 32
in tht case u need to subtract 14 on both sides to isolate x

Answer 13

when its like 14x = 56
in this case u need to divide by 14

Answer 14

right i see now i have another question like this one can you help me?

Answer 15

okkk :))

Answer 16

im not sure what base they both would be at

Answer 17

im thinking that it doesnt have a solution

Answer 18

see in this type of question u need to equalize the base on both sides.
like write 64 = 2^6 and 512 = 2^8
now proceed

Answer 19

right then i did \[6(3x)=9(2x+12)\]

Answer 20

and got \[18x=18x+108\]

Answer 21

is that right

Answer 22

so no solution :)) good work :))

Answer 23

thank you

Answer 24

u r most welcome :)))

Answer 25

can you check my work for this one please?

Answer 26

whts ur answer ??

Answer 27

i did \[3b-1=b-3\]

Answer 28

okk....whts ur answer???

Answer 29

i got -1.5 but its not an answer so i dont know what i am doing wrong

Answer 30

lol nah..... how 1.5???huh???
see first of all u need to add one on both sides..and then subtrtact b on both sides

Answer 31

i added 3 to both sides

Answer 32

so it would be 1

Answer 33

if u added 3 tht correct but how 1??
see 3b + 2 = b
now u need to isolate b ..so subtract 3b on both sides

Answer 34

so
2 = -2b
b = -1

Answer 35

@heacain ??????

Answer 36

i see now sorry my computer is acting up!!

Answer 37

i just have one more is that okay?

Answer 38

u tell me this time....

Answer 39

how can u equalize the base

Answer 40

you would change \[25^x \to 5^2\]

Answer 41

girl see ...
25 = 5^2

Answer 42

\[5^{2x}=5^{x2-3}\]

Answer 43

this is where im confused what do you do with the extra 2

Answer 44

lol u mean
\[5^{2x} = 5^{x^2 - 3}\]

Answer 45

its x^2

Answer 46

yea sorry

Answer 47

lol okay :))

Answer 48

would you just leave it off and solve without it

Answer 49

wht do u mean???

Answer 50

would solve without it like \[5^{2x}=5^{x-3}\]

Answer 51

would it be -3 and 1

Answer 52

nope its -1 and 3

Answer 53

i was close just had the wrong signs

Answer 54

u need to solve \[2x = x^2 -3 \]

Answer 55

im not sure how to do that

Answer 56

so u need to solve
x^2 - 2x - 3 = 0

Answer 57

http://www.purplemath.com/modules/solvquad.htm

Answer 58

you factor than you would get the answer

Answer 59

lol yeah :))

Answer 60

i see now thank you :)

Answer 61

u r most welcome :)_))) @heacain

Answer 62

i might have more questions in the next section that i am learning.

Answer 63

ok :)))