Question

Quick conceptual question. Regarding Electric Potential and Electric Fields. Question on picture:
https://i.gyazo.com/7616728619436b3d4308ac49177bda86.png

I'd like both the answer and the explanation of why. Thanks!

Answer 1

Picture of the question.

Answer 2

i'd use \(E = - \dfrac{dV}{dx}\) to work this


this explains the equation: http://farside.ph.utexas.edu/teaching/302l/lectures/node34.html but sure you know it anyway


you can see what E(x) is doing just by plugging in some simple (this is a crude method) numbers. NB if dx is positive as you move left to right, then dV is negative, so E is pos

Answer 3

What IrishBoy123's equation is also saying is that the electric field can be expressed in volts per metre V/m.
So, the faster the rate of change of V with regard to space, the greater the E-field.

Answer 4

So the electric field is increasing then?

Answer 5

Correct :))

Answer 6

Oh great I think I got it then, thanks alot!