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I would truly be ve… - QuestionCove
OpenStudy (anonymous):

I would truly be very thankful if any of you could please help me identify how to solve the following problem and help me do so. I am merely trying to go through my wrong answers so when I do get my test, I can actually do well.

1 year ago
OpenStudy (anonymous):

1 year ago
OpenStudy (redstealth29):

I'll do my best to assist. Tag me in your posts

1 year ago
OpenStudy (redstealth29):

Damn it, I have to go offline, i'm sorry. @iGreen please help this person. Bye!!

1 year ago
OpenStudy (anonymous):

thank you either way. I just don't get what I'm supposed to do with the ratio

1 year ago
OpenStudy (fortytherapper):

I have a way, but I don't know if it'll be confusing. I can try to explain if you want

1 year ago
OpenStudy (anonymous):

Please do, anything might be helpful.

1 year ago
OpenStudy (fortytherapper):

So I first set up the proportion \[\frac{ 11 }{ (180-x) } = \frac{ 25 }{ x }\] Any questions on any of these values?

1 year ago
OpenStudy (anonymous):

Well, it makes sense, I had set up the proportion wrong I guess. why minus x though?

1 year ago
OpenStudy (fortytherapper):

Let's say one angle, x, is 12 degrees Supplementary angles equal 180 degrees, so the other angle is 180-12, or 180-x

1 year ago
OpenStudy (anonymous):

ah I see, yes, so your proportion is saying?

1 year ago
OpenStudy (fortytherapper):

It's saying that 11 is being compared to the smaller angle, and 25 to the largest. In order to find that, we must cross multiply and divide

1 year ago
OpenStudy (anonymous):

Okay now I understand.

1 year ago
OpenStudy (fortytherapper):

Nice! Lemme know if you can find x

1 year ago
OpenStudy (anonymous):

oh yes I got 125, which is correct. Hmm so I guess my mistake is setting the proportions.

1 year ago
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