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OpenStudy (anonymous):
OpenStudy (freckles):
you could plug in the integers from n=3 to n=8 (inclusive)
and add the terms
OpenStudy (freckles):
f(n)=5n
f(3)=?
f(4)=?
f(5)=?
f(6)=?
f(7)=?
f(8)=?
then add those results
OpenStudy (anonymous):
So wait id just add them normally?
OpenStudy (isaidavila):
Or you can put the summation as
5 times the sum of 3 to 8
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OpenStudy (anonymous):
38?
OpenStudy (anonymous):
thats what igot
OpenStudy (freckles):
yes...I think...what does normally mean? Do you do it non-normally sometimes :p
this isn't the only way to do this problem
there are formulas you could use but you have to be clever since the bottom limit is n=3 and not n=1
OpenStudy (anonymous):
like 5+5=10
OpenStudy (isaidavila):
Just sum 3+4+5+6+7+8 and multiply by 5
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OpenStudy (anonymous):
ahhhhh
ok
OpenStudy (freckles):
how did you get 38
OpenStudy (anonymous):
65?
OpenStudy (anonymous):
I just didnt multiply the 5 before
OpenStudy (freckles):
\[f(n)=5n \\ f(3)=5(3) \\ f(4)=5(4) \\ f(5)=5(5) \\ f(6)=5(6) \\ f(7)=5(7) \\ f(8)=5(8) \\ \text{ adding lines 2 through 6 } \\ \text{ should give you a number over 100 }\]
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OpenStudy (isaidavila):
You mean 165?
OpenStudy (anonymous):
how though?
OpenStudy (anonymous):
Just sum 3+4+5+6+7+8 and multiply by 5
OpenStudy (anonymous):
Thats what you said
OpenStudy (isaidavila):
Sum 3+4+5+6+7+8=33 then 33*5=??
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OpenStudy (anonymous):
yeah idk i probably messed up something on my calculator, im sleepy
OpenStudy (anonymous):
but thank you
OpenStudy (isaidavila):
Ok no problem
OpenStudy (anonymous):
help with one more?
OpenStudy (isaidavila):
Hmm ok
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