Question

Rider A: y=3/2x Rider B: y=1/2x+10

Use the equal values method to determine what time rider A passed RiderB: How far from the starting line were the two racers at that time ?

Answer 1

@mathmale

Answer 2

@kittiwitti1

Answer 3

Si?

Answer 4

I need help with that question

Answer 5

I need help solving it

Answer 6

I don't know e_e

Answer 7

I'm sorry ; -;

Answer 8

2 (3/2x=1/2x+10)

Answer 9

!

Oh wait... you set the functions equal to each other right

Answer 10

yes

Answer 11

Oh, okay. Yeah you're on the right path (:

Answer 12

Then I distribute ?

Answer 13

Yep ☺

Answer 14

\[2(\frac{3}{2}x)=2(\frac{1}{2})+2(10)\rightarrow 3x=1+20\]So 3x=21

Answer 15

Yep ♪

Answer 16

Then add 3x on both sides

Answer 17

Whoa, going a little overboard there lol
Nope, did you see what I did ♦

Answer 18

subtract 3x on both sides lol

Answer 19

Um.. No o_o?

Answer 20

divide

Answer 21

Yeah ☺

Answer 22

x=7

Answer 23

Yes!! ☺☺

Answer 24

I don't know on what equation I should plug it in

Answer 25

Either one works I think

Answer 26

So I could plug it in with 1/2x+10 right ?

Answer 27

Is that wrong or right ??

Answer 28

Sorry! Yeah, it works ♦

Answer 29

its okay

Answer 30

I got 13.5

Answer 31

??? That's right but it's weird o_e

Answer 32

or as a fraction is 27/2

Answer 33

OH WE MESSED UP

Answer 34

It's x+20 not 1+20

Answer 35

Wait for the equation ??

Answer 36

Yeah lol
I'm so sorry > <

Answer 37

its okay

Answer 38

So all of its wrong?

Answer 39

Okay so it's \[\frac{1}{2}x=\frac{3}{2}x+10\]\[2\left(\frac{1}{2}x\right)=2\left(\frac{3}{2}x\right)+2(10)\]

Answer 40

It's not wrong, we just left out an x. I'm redoing it so we don't mess up again is all ♦

Answer 41

\[\rightarrow x=3x+20\]\[-4x=20...\]

Answer 42

x=-5

Answer 43

Is it right ?

Answer 44

Yes ☺

Answer 45

plug it in and y=2.5 or as a fraction 5/2

Answer 46

Yes ♪

Answer 47

Except it's negative, don't forget that

Answer 48

oh okay

Answer 49

thanks

Answer 50

np ☺