A positive charge 'q' of mass 'm' is moving along the x-axis a uniform magnetic field B for time delta t so that the charge reverses its direction crossing the y-axis at a distance d. Then find B and delta t
@samigupta8 @ganeshie8
Is ∆t=πm/Bq And B=2mv/qd
how?
Are they right??
B is correct but delta t is not..
can you tell me how did you solve for b?
*B
Sure!! Just a sec i m trying to figure out mistake in ∆t
ok
@samigupta8 ?
just tell me this how will the radius of its path be d/2 ?
and how can we say v is perpendicular to B?
U simply check it from the options.. If there is no perpendicular velocity to B then we can't have the circular motion of the particle.
And will you pls tell of which jee paper is this question from .. I m unable to find it in my book.. Pls do tell so that i may confirm my ans..
i know .. thats why i asked how is B perpendicular to v and how can it reverse the direction?
Why not ?? B has a great knack to do all these things straightaway...
Okk i will tell you how??
can you pls explain a bit more conceptually ?
I got the ans It is ∆t=πd/2v
oh thats right! can you pls explain a bit more conceptually ?
Okk priyar u know that ven particle will enter magnetic field and due to that it will be feeling a magnetic force on it...
yeah! F= q(vxB)
This magnetic force will cause it to move it in a circular path.. Now we want that particle should just cross the y axis at d distance from y axis so that means centre must be at distance d/2 from origin.. Ryt??
ok but the part which i am not getting is how is it a circular path and how B reverse the direction of v
Magnetic force is the reason for its circular motion
U analyse the situation by luking at the concept that when it will reach distance d then force is acting towards centre and so the particle must have the velocity opposite in direction to what it had initially at the start of motion
the magnetic force must be acting in the opp dir. right?
@samigupta8
Opposite direction to what??
opp to its direction of motion... only then it can reverse the dir. by 180 degrees right?
How .. F=q(v*B) How can force be ever opposite to direction of motion for a particle in uniform magnetic field
that is what i came to ask you.. so how is this situation possible?
i got the values of B and delta t if i take it to be circular.. but why circular?
U r not trying to understand.. Force direction is always towards centre of circular path so just do that and let go the particle at distance d from origin on y axis .. U will see what i want to tell by this ??
Draw a diagram for that in ur notebook and see the diff
ok thanks
U get it??
think so
Great!!
there can be 2 possibilities of circular motion right? either it can move in a circular motion and go further away from the origin or it can come in a circle towars origin... in what dir. must B act for the charge to come towards origin? @samigupta8
+j right?
It can be in any direction k or -k
how? we need the charge to come toward origin right?
How can u direct your force in k direction by assuming magnetic field to be in y direction?? We want it to cross y axis and not z axis
ya... i was keeping the axes diff for understanding.. and forgot to change it according to this Q..
anyway, is there two possibilities of circular motion or not?
Yep there can be bt we want it to be like that mentioned in question.. So go as per they suggest in the question
then how can u say particle will cross y axis no matter what direction B acts...??
I asked you to consider the case when particle is moving such that it completes a half circle in magnetic field
thats not what i m asking...
Thanks anyway! @samigupta8
@samigupta8 i got it!
B can act only in one direction for this to be possible
Wohooo!!! That is ??
that is -k!!!!
Even k would do .. Consider it too!!
i considered it.. but it gives the other possibility that i told you
Then the particle would cross a distance d in negative y direction.. That's it!!
no.. it will move farther away from x- axis.. as i told you before.. those two cases.. remember?!
Both the possibility in k and -k certainly don't give the possibility of that what u told me bcoz that's the case when magnetic field is restricted to a certain region..and that's not mentioned here.. So consider it to be present throughout the motion of particle
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