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MIT OCW Physics 8 Online
OpenStudy (priyar):

A positive charge 'q' of mass 'm' is moving along the x-axis a uniform magnetic field B for time delta t so that the charge reverses its direction crossing the y-axis at a distance d. Then find B and delta t

OpenStudy (priyar):

@samigupta8 @ganeshie8

OpenStudy (samigupta8):

Is ∆t=πm/Bq And B=2mv/qd

OpenStudy (priyar):

how?

OpenStudy (samigupta8):

Are they right??

OpenStudy (priyar):

B is correct but delta t is not..

OpenStudy (priyar):

can you tell me how did you solve for b?

OpenStudy (priyar):

*B

OpenStudy (samigupta8):

Sure!! Just a sec i m trying to figure out mistake in ∆t

OpenStudy (priyar):

ok

OpenStudy (priyar):

@samigupta8 ?

OpenStudy (priyar):

just tell me this how will the radius of its path be d/2 ?

OpenStudy (priyar):

and how can we say v is perpendicular to B?

OpenStudy (samigupta8):

U simply check it from the options.. If there is no perpendicular velocity to B then we can't have the circular motion of the particle.

OpenStudy (samigupta8):

And will you pls tell of which jee paper is this question from .. I m unable to find it in my book.. Pls do tell so that i may confirm my ans..

OpenStudy (priyar):

i know .. thats why i asked how is B perpendicular to v and how can it reverse the direction?

OpenStudy (samigupta8):

Why not ?? B has a great knack to do all these things straightaway...

OpenStudy (samigupta8):

Okk i will tell you how??

OpenStudy (priyar):

can you pls explain a bit more conceptually ?

OpenStudy (samigupta8):

I got the ans It is ∆t=πd/2v

OpenStudy (priyar):

oh thats right! can you pls explain a bit more conceptually ?

OpenStudy (samigupta8):

Okk priyar u know that ven particle will enter magnetic field and due to that it will be feeling a magnetic force on it...

OpenStudy (priyar):

yeah! F= q(vxB)

OpenStudy (samigupta8):

This magnetic force will cause it to move it in a circular path.. Now we want that particle should just cross the y axis at d distance from y axis so that means centre must be at distance d/2 from origin.. Ryt??

OpenStudy (priyar):

ok but the part which i am not getting is how is it a circular path and how B reverse the direction of v

OpenStudy (samigupta8):

Magnetic force is the reason for its circular motion

OpenStudy (samigupta8):

U analyse the situation by luking at the concept that when it will reach distance d then force is acting towards centre and so the particle must have the velocity opposite in direction to what it had initially at the start of motion

OpenStudy (priyar):

the magnetic force must be acting in the opp dir. right?

OpenStudy (priyar):

@samigupta8

OpenStudy (samigupta8):

Opposite direction to what??

OpenStudy (priyar):

opp to its direction of motion... only then it can reverse the dir. by 180 degrees right?

OpenStudy (samigupta8):

How .. F=q(v*B) How can force be ever opposite to direction of motion for a particle in uniform magnetic field

OpenStudy (priyar):

that is what i came to ask you.. so how is this situation possible?

OpenStudy (priyar):

i got the values of B and delta t if i take it to be circular.. but why circular?

OpenStudy (samigupta8):

U r not trying to understand.. Force direction is always towards centre of circular path so just do that and let go the particle at distance d from origin on y axis .. U will see what i want to tell by this ??

OpenStudy (samigupta8):

Draw a diagram for that in ur notebook and see the diff

OpenStudy (priyar):

ok thanks

OpenStudy (samigupta8):

U get it??

OpenStudy (priyar):

think so

OpenStudy (samigupta8):

Great!!

OpenStudy (priyar):

there can be 2 possibilities of circular motion right? either it can move in a circular motion and go further away from the origin or it can come in a circle towars origin... in what dir. must B act for the charge to come towards origin? @samigupta8

OpenStudy (priyar):

+j right?

OpenStudy (samigupta8):

It can be in any direction k or -k

OpenStudy (priyar):

how? we need the charge to come toward origin right?

OpenStudy (samigupta8):

How can u direct your force in k direction by assuming magnetic field to be in y direction?? We want it to cross y axis and not z axis

OpenStudy (priyar):

ya... i was keeping the axes diff for understanding.. and forgot to change it according to this Q..

OpenStudy (priyar):

anyway, is there two possibilities of circular motion or not?

OpenStudy (samigupta8):

Yep there can be bt we want it to be like that mentioned in question.. So go as per they suggest in the question

OpenStudy (priyar):

then how can u say particle will cross y axis no matter what direction B acts...??

OpenStudy (samigupta8):

I asked you to consider the case when particle is moving such that it completes a half circle in magnetic field

OpenStudy (priyar):

thats not what i m asking...

OpenStudy (priyar):

Thanks anyway! @samigupta8

OpenStudy (priyar):

@samigupta8 i got it!

OpenStudy (priyar):

B can act only in one direction for this to be possible

OpenStudy (samigupta8):

Wohooo!!! That is ??

OpenStudy (priyar):

that is -k!!!!

OpenStudy (samigupta8):

Even k would do .. Consider it too!!

OpenStudy (priyar):

i considered it.. but it gives the other possibility that i told you

OpenStudy (samigupta8):

Then the particle would cross a distance d in negative y direction.. That's it!!

OpenStudy (priyar):

no.. it will move farther away from x- axis.. as i told you before.. those two cases.. remember?!

OpenStudy (samigupta8):

Both the possibility in k and -k certainly don't give the possibility of that what u told me bcoz that's the case when magnetic field is restricted to a certain region..and that's not mentioned here.. So consider it to be present throughout the motion of particle

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