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hi who wanna help
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where's the question :D
HOLD
\[\sqrt[3]{8}-20x+2^2+4x\]
@wcrmelissa2001
whts \[\sqrt[3]{8}\]
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ITS 2
Lol
its 2 silly just 2
\[btw i forgot the equals\]
2+20x=4-4x
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Is that the question
or have you reformulated it
\[\sqrt[3]{8}\] so basically 8=2^3 so you get 3√ 2^3 So in other words it's 2^3/3 = 2^1=2
i simplified it
@jjcoolja12 He simplied it wrong. SO you should've seen the simplification first
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\[here is the original \]
i actually seen that but i accidentally hit post
\[\sqrt{16x}-x2+2\times 40|2\]
that is the original
i gtg
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