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Mathematics 7 Online
OpenStudy (anonymous):

hi who wanna help

OpenStudy (wcrmelissa2001):

where's the question :D

OpenStudy (anonymous):

HOLD

OpenStudy (anonymous):

\[\sqrt[3]{8}-20x+2^2+4x\]

OpenStudy (anonymous):

@wcrmelissa2001

rishavraj (rishavraj):

whts \[\sqrt[3]{8}\]

OpenStudy (anonymous):

ITS 2

OpenStudy (error1603):

Lol

OpenStudy (anonymous):

its 2 silly just 2

OpenStudy (anonymous):

\[btw i forgot the equals\]

OpenStudy (anonymous):

2+20x=4-4x

OpenStudy (faiqraees):

Is that the question

OpenStudy (faiqraees):

or have you reformulated it

OpenStudy (wcrmelissa2001):

\[\sqrt[3]{8}\] so basically 8=2^3 so you get 3√ 2^3 So in other words it's 2^3/3 = 2^1=2

OpenStudy (anonymous):

i simplified it

OpenStudy (faiqraees):

@jjcoolja12 He simplied it wrong. SO you should've seen the simplification first

OpenStudy (anonymous):

\[here is the original \]

OpenStudy (jjcoolja12):

i actually seen that but i accidentally hit post

OpenStudy (anonymous):

\[\sqrt{16x}-x2+2\times 40|2\]

OpenStudy (anonymous):

that is the original

OpenStudy (anonymous):

i gtg

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