Question

FAN AND MEDAL
find a quadratic function in standard form for each set of points (0,-4), (1,0), (2,2)

Answer 1

@xMissAlyCatx @texaschic101 @dayakar @zepdrix

Answer 2

Do you know what quadratic function and standard form are?

Answer 3

yes, i learned them a long time ago but idk how to make these points like them

Answer 4

im v confused @xMissAlyCatx

Answer 5

how do i get a b and c?

Answer 6

@Compassionate @ParthKohli

I honestly don't know how to explain this so here you go..

Answer 7

anyone? i really need help with this @texaschic101 @dayakar @zepdrix

Answer 8

\[y = ax ^{2}+bx +c\]

Answer 9

okay but i still dont understand how you get a, b, and c

Answer 10

(x1,y1) =(0, -4), (x2, y2) =(1,0) , (x3,y3) = (2,2)
plug each one in the above equation
u can get 3 equations

Answer 11

-4 = a* 0^2 +b*0 +c[ plug in first one]
-4 =c
c= -4 -------(1)

Answer 12

do u understand

Answer 13

plz , respond

Answer 14

0 = a*1^2 +b* 1 +c [ plug in second in the equation]

0 = a+ b -4 [ from (1) c= -4] ------(2)

Answer 15

sorry my wifi was glitching

Answer 16

2= a*2^2 + b*2 +c [ plug in third]
2 = 4a +2b -4 [ from (1) ,c= -4]

divide each term with 2
u can get
1= 2a +b -2 -----(3)

subtract (2) from (3)
u can get a value

Answer 17

1?

Answer 18

@dayakar

Answer 19

so does b = 1

Answer 20

a= -1

Answer 21

plug a=-1 in (2)

Answer 22

is it clear

Answer 23

im confused where im plugging in a =-1

Answer 24

c = -4 right

Answer 25

equation (2)
0= a+b-4

Answer 26

0=b-5?

Answer 27

we get c = -4 very beginning of the solution

Answer 28

okay, so does b = 5?

Answer 29

0 = -1 +b -4
0= -5+b
5=b
b=5

Answer 30

there fore a= -1, b= 5, c=-4
write in the standard form
y= ax^2+bx+c

y= -1x^2 +5x-4

Answer 31

OHHHH okay that makes sense

Answer 32

if i post another could u help me?

Answer 33

i'll try