Why is my answer not correct? I think its 1/2 but the answer key says the answer is 2/45. Can someone explain why? Thank you :) A bag of fruit contains 3 apples, 2 oranges, 1 banana, and 4 pears. Gerald will randomly select two pieces of fruit one at a timefrom the bag and not put them back. What is the probability that the first piece of fruit gerald selects will be a banana and the second piece of fruit will be a pear
I got 1/2 by adding 1(banana) and 4(pear) which would be 5/10 (total amount of fruits) which is equivalent to 1/2
Calculate the odds of getting a banana, then separately, the odds of getting a pear after that, and multiply the results together.
Banana = 1/10 Pear = 4/9 (Because we've removed one of the 10 pieces of fruit already)
No thats the wrong method. To calculate the probabilty of two "related event" you have to multiply the probabiltiy of getting a banana by the probability of getting a pear
Now the probability of getting a banana = 1/10 (since 1 banana and 10 fruits) probability of getting a pear = 4/9 (since 4 pears and 9 fruits ) Probability = 4/9 x 1/10
Thank you all !
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