Algebra II Simplify square root 72 minus 3 times square root 12 plus square root of 192.
factor out 12 under each radical. so sqrt(12*6)-3*sqrt(12)+sqrt(16*12). Factor out sqrt(12) to get sqrt(12)*(sqrt(6)+1)
Okay, thank you.
If I factor out 12 from the square root of 72 I would get: 6 Square root of 2?
\[6\sqrt{2}\]
\[\Large \sqrt{72} = \sqrt{36*2}\] \[\Large \sqrt{72} = \sqrt{36}*\sqrt{2}\] \[\Large \sqrt{72} = 6\sqrt{2}\]
I mean if you simplify it down...\[6\sqrt{2} + 2\sqrt{3} \]
You can get your final answer out of this.
Okay, as I solved the problem further I got that as my answer.
Also, I need help with the following question: Simplify the expression fraction with numerator of the square root of negative four and denominator of the quantity three plus i minus the quantity two plus three times i.
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