Question

Which hyperbola has both vertices in the same quadrant?
Will fan and medal!

Answer 1

a) \[\frac{ (x+10)^2 }{11^2 }-\frac{ (y-3)^2 }{ 10^2 }=1\]
b)\[\frac{ (y-8)^2 }{ 9^2}-\frac{ (x+6)^2 }{ 12^2 }=1\]
c) \[\frac{ (x-1)^2 }{ 12^2}-\frac{ (y-11)^2 }{ 8^2 }=1\]
d) \[\frac{ (y-10)^2 }{ 9^2 }-\frac{ (x+1)^2 }{ 11^2 }=1\]

Answer 2

@jigglypuff314

Answer 3

@robtobey

Answer 4

@SolomonZelman

Answer 5

this problem is a pain in the neck! you have to find the vertices for each one!!

Answer 6

if it was me, i would cheat
vertices of the first one: \((-21,3),(1,3)\) so not that one

Answer 7

answer is usually C, so i tried that next
not that one either though