K its midnight and I need HELP!!!! Will fan and medal!
the sum of the digits of a 3-digit number is 21. The sum of the ten's hundreds digits is 3 less than twice the unit's digit. The number is increased by 198 if the digits are reserved. Find the original number
Number xyz x+y+z=21 x+y=2z-3 xyz=zyx-198 Using the first 2 equations (substitution), you find that z=8. This means that x+y=13 Using the last equation, after you know that z=8, you can infer that the number must start with a 6 in order to satisfy the increased by 198 rule. Thus, x=6. Plug it in to x+y=13, y=7. xyz is 678
@ijakez How did you get "6"? That's the only question I have!!
xy8=8yx-198??
because you know z is 8, using the last equation you have xy8=8yx-198 and x+y=13. You now know that x has to be 6 because 8yx-198 must equal 6y8
@ijakez Thank for this help. Really means a lot to me
Happy to help!
Join our real-time social learning platform and learn together with your friends!