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Mathematics 7 Online
OpenStudy (anonymous):

Simplify (2x+1)(3x+4) A: 2x(2x+3)+3(3x+4) B: 2x(3x+4)+3(3x+4) C: 2x(3x+4) D: 2x(3x+4)+(3x+4)

OpenStudy (kayders1997):

Distribute for these

OpenStudy (kayders1997):

Oh I see

OpenStudy (kayders1997):

For the top you need to use the FOIL method

OpenStudy (anonymous):

When I use the foil method I get some answer starting w/ 6x?

OpenStudy (kayders1997):

Yes 6x^2

OpenStudy (anonymous):

noo it has to be one of the listed answers. i can't figure out how to get one of them.

OpenStudy (kayders1997):

Yeah I've been looking, none of them seem correct

OpenStudy (anonymous):

:(

OpenStudy (kayders1997):

wait!!!!!

OpenStudy (kayders1997):

Your adding the terms I was multiplying in the MC answers

OpenStudy (kayders1997):

So what did you get when you foiled out that expression? (2x+1)(3x+4)

OpenStudy (kayders1997):

6x^2+?

OpenStudy (anonymous):

no 6x^2+11x+4

OpenStudy (kayders1997):

Yes good

OpenStudy (kayders1997):

Now what answer will give you 6x^2

OpenStudy (kayders1997):

You can eliminate some right off the bat

OpenStudy (kayders1997):

Does 2x times 2x give you 6x^2?

OpenStudy (anonymous):

c???

OpenStudy (kayders1997):

That is not right because it won't give you 11x

OpenStudy (kayders1997):

So not A or C is there an e in the problem?

OpenStudy (anonymous):

that was a typo, i meant to put a 3

OpenStudy (kayders1997):

Oh okay!

OpenStudy (kayders1997):

So it's b or d

OpenStudy (kayders1997):

Let's just look let's expand B 2x(3x+4)+3(3x+4) so multiply the 2x but the inside parenthesis and the 3 inside the other parenthesis than add like terms

OpenStudy (kayders1997):

Let me know what you get when you do that

OpenStudy (anonymous):

i'm so confused :((( i calculated D w/ wolfram alpha and it gets the same result as the initial problem put into a foil calculator so is it d?

OpenStudy (kayders1997):

It is D do you need me to explain why it is D?

OpenStudy (anonymous):

yes pls

OpenStudy (kayders1997):

2x(3x+4)+(3x+4) first we are going to distribute the 2x into the the parenthesis so we do 2x times 3x=6x^2 than the second part 2x times 4 which equals 8x and than we are adding everything now so we have 6x^2+8x+3x+4 so now we just add like terms so our x's are the same terms so we can add 8x+3x=11x so we get back to 6x^2+11x+4

OpenStudy (kayders1997):

If something doesn't make sense please let me know

OpenStudy (anonymous):

thank u so much

OpenStudy (kayders1997):

You're welcome :)

OpenStudy (kayders1997):

Any others? :)

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