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Which of the following completes Jake's proof? Select one: a. In triangles APD and BPC; AD = BC b. In triangles APD and BPC; AP = PB c. In triangles APB and DPC; AD = BC d. In triangles APB and DPC; AP = PB
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@mathstudent55
Well, the last step uses SAS, so what is missing? A side angle or side?
@mathmale
I'm not sure lol @anthonyym I don't get Geometry
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SAS means side-angle-side. It's a way of proving that two triangles are congruent. If two triangles have two congruent sides and the angle between those congruent angles is the same, then the triangles are congruent. Do you understasnd SAS?
I understand now. Is the answer A?
Yes A would be correct.
Sorry I mistyped something. It should say "and the angle between those congruent sides"
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