Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (samanthagreer):

What is the value of x? Round your answer to the nearest tenth if necessary. http://prntscr.com/aomlhh

OpenStudy (simplymarie_x):

Use the Pythagorean theorem I believe. a^2 + b^2 = c^2 7 is leg a. 4 is leg b. You can just plug them in and solve ^~^

rebeccaxhawaii (rebeccaxhawaii):

^^

rebeccaxhawaii (rebeccaxhawaii):

\[a^2+b^2=c^2\]

OpenStudy (simplymarie_x):

^ That.

OpenStudy (samanthagreer):

ok so 7 ^2 + 4 ^2 = c^2

OpenStudy (simplymarie_x):

Yes.

OpenStudy (simplymarie_x):

Do you know the next step? ^~^

OpenStudy (samanthagreer):

no i dont can you explain

OpenStudy (simplymarie_x):

Okay. so 7^2 + 4^2 = c^2 is the same as 49 + 16 = c^2 Then 49 + 16 = 65. so 65 = c^2. Then to get rid of the power on c, you have to do the square root of 65.

OpenStudy (samanthagreer):

would you divide 65 by 2

OpenStudy (simplymarie_x):

\[65 = c ^{2}\] \[\sqrt{65}\] \[\sqrt{65} = 8.0622577\]

OpenStudy (simplymarie_x):

(Not sure why that got deleted sorry) So then you round 8.0622577 to the nearest tenth giving you 8.1

OpenStudy (simplymarie_x):

So ultimately x = 8.1

OpenStudy (samanthagreer):

oh ok that make sece can you help me throguth another

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!