What is the value of x? Round your answer to the nearest tenth if necessary. http://prntscr.com/aomlhh
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OpenStudy (simplymarie_x):
Use the Pythagorean theorem I believe.
a^2 + b^2 = c^2
7 is leg a.
4 is leg b.
You can just plug them in and solve ^~^
rebeccaxhawaii (rebeccaxhawaii):
^^
rebeccaxhawaii (rebeccaxhawaii):
\[a^2+b^2=c^2\]
OpenStudy (simplymarie_x):
^ That.
OpenStudy (samanthagreer):
ok so 7 ^2 + 4 ^2 = c^2
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OpenStudy (simplymarie_x):
Yes.
OpenStudy (simplymarie_x):
Do you know the next step? ^~^
OpenStudy (samanthagreer):
no i dont can you explain
OpenStudy (simplymarie_x):
Okay. so 7^2 + 4^2 = c^2 is the same as
49 + 16 = c^2
Then 49 + 16 = 65.
so 65 = c^2.
Then to get rid of the power on c, you have to do the square root of 65.
OpenStudy (samanthagreer):
would you divide 65 by 2
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OpenStudy (simplymarie_x):
\[65 = c ^{2}\]
\[\sqrt{65}\]
\[\sqrt{65} = 8.0622577\]
OpenStudy (simplymarie_x):
(Not sure why that got deleted sorry)
So then you round 8.0622577 to the nearest tenth giving you 8.1
OpenStudy (simplymarie_x):
So ultimately x = 8.1
OpenStudy (samanthagreer):
oh ok that make sece can you help me throguth another