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Mathematics 17 Online
OpenStudy (mathmath333):

question(logical reasoning) 16 teams have been invited to participate in ...

OpenStudy (mathmath333):

OpenStudy (mathmath333):

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OpenStudy (mathmath333):

\(\large \color{black}{\begin{align} \begin{array}{|c|c|c|c|c|c|c|c|c|c|} \hline & a & b & c & d & e & f & g & h & total \\ \hline a & \times & 1 & 1 & 1 & 0 & 0 & 0 & 0 & 3 \\ \hline b & 0 &\times & 1 & 0 & 1 & 0 & 1 & 0 & 3 \\ \hline c & 0 & 0 &\times & 1 & 0 & 1 & 0 & 1 & 3 \\ \hline d & 0 & 1 & 0 &\times & 1 & 0 & 1 & 0 & 3 \\ \hline e & 1 & 0 & 1 & 0 & \times& 1 & 0 & 1 & 4 \\ \hline f & 1 & 1 & 0 & 1 & 0 & \times& 1 & 0 & 4 \\ \hline g & 1 & 0 & 1 & 0 & 1 & 0 & \times& 1 & 4 \\ \hline h & 1 & 1 & 0 & 1 & 0 & 1 & 0 & \times& 4 \\ \hline \end{array} \end{align}}\)

OpenStudy (mathmath333):

i think the answer is 4

OpenStudy (reemii):

Maybe.. I think so too but , no proof?

OpenStudy (mathmath333):

but i displayed it in the table

OpenStudy (mathmath333):

i proved it i think

OpenStudy (reemii):

Maybe, I (team a) have 4 points, but 4 other teams have 5 points... I am not going to stage 2.. Is the situation I'm describing impossible?

OpenStudy (mathmath333):

the question is asking only for stage 1

OpenStudy (reemii):

Yes. If a score sheet like (5,5,5,5, 4 (my team), 2, 2, 0) exists, then I am not going to the next stage. It's certain that (6,6,6,6,5,...) doesn't exist : too many points (at least 6+6+6+6+5 = 29).

OpenStudy (reemii):

The answer is 4 or 5.

OpenStudy (mathmath333):

but question is asking the minimum and 4 is minimum not 5

OpenStudy (reemii):

You have found the table for another question: "what is lowest possible score for the 4 selected teams?" The real question is: "If a team tells you 'we got 4 points', are you sure that they are selected for the next stage?" it's different.

OpenStudy (mathmath333):

ok so 4 is not the answer 6 is

OpenStudy (mathmath333):

i failed to understood the question

OpenStudy (reemii):

Not 6. It's true that a team with 6 points will be selected, but maybe it's already ok with 5. If you can find a table with 4 teams having 5 points, and "myteam" having 4 points, then 4 is not the answer.

OpenStudy (mathmath333):

but in my book it says 6

jhonyy9 (jhonyy9):

yes - this is exactly same with the football selectinarie groups when begining the matches - games with 16 teams separated in 2 groups with 8 and 8 teams and after the first round when every team playing one match with the other teams and just the winners will be selected in the next round - there are 2 groups with 8 and 8 teams - so from this result that every team play in the first round 7 matches and bc. from these 8 team the first 4 will be selected in the next round so from 7 matches are possibille acumulate max. 7 points and every 8 teams not can accumulate 7 points so from this result that the team what accumulated 6 points will be selected in the next round sure,secure - hope this is understandably sure right

OpenStudy (mathmath333):

can u show a case where team with 5 points is not selected

OpenStudy (mathmath333):

@jhonyy9

OpenStudy (mathmath333):

@Bobo-i-bo

hartnn (hartnn):

6,5,5,5,5 (your team), ... does not guarantee your selection.

hartnn (hartnn):

because there is a possibility that the tie resolved by "tie-breaking" rules, eliminate your team.

OpenStudy (mathmath333):

oh right

OpenStudy (mathmath333):

hartnn is very intelligent

hartnn (hartnn):

not actually, but thanks :)

OpenStudy (reemii):

@mathmath333 . I didn't mean '6' is impossible.. you have to check 5 vs 6. But, look, it's solved 👻 .

OpenStudy (mathmath333):

\(\Huge 👻\ ok\)

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