WILL MEDAL AND FAN!
Perform the following operations and write the answers in rational exponent form.
√7 + √3 + √98 - √18
and
3√5 - 3√11 + 2√121 -3√90
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OpenStudy (anonymous):
@SerenityJustice74
OpenStudy (anonymous):
@leonardo0430
OpenStudy (serenityjustice74):
Sorry, I was messging my friend. Okay what do you think? Where can you start?
Think about PEMDAS
OpenStudy (anonymous):
That's what I thought, but I was absent this day and didn't know if there was a certain way to do this.
OpenStudy (serenityjustice74):
Oh you have to simplify it as well. Do you know how to break down square roots into simple forms?
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OpenStudy (anonymous):
Yeah, don't you have to find factors of them or something?
OpenStudy (serenityjustice74):
Hmm yes, kinda. You get the factors of the number and make sure one of them can be square rooted so you can keep the other inside the square root.
@Mehek14 teach please. i feel depressed.
OpenStudy (anonymous):
@ParthKohli
Mehek (mehek14):
we have to simplify √98 and √18
list their factors
OpenStudy (anonymous):
2 * 49 and 2*9
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OpenStudy (anonymous):
is that all?
Mehek (mehek14):
so √98 = 7√2 and √18 = 3√2
now we have:
√7 + √3 + 7√2- 3√2
we can combine 7√2 - 3√2
just subtract 7 - 3
OpenStudy (anonymous):
alright, and that's it?
Mehek (mehek14):
well tell me what u get :)
OpenStudy (anonymous):
/ = radical
/4 + 4/2
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Mehek (mehek14):
o-0 what
OpenStudy (anonymous):
idk what im doing
Mehek (mehek14):
all you have to do is combine 7√2 - 3√2
and to do that, subtract 7 - 3 and keep √2 as is
OpenStudy (anonymous):
oh ok
so √7 + √3 - 4√2?
Mehek (mehek14):
positive 4
√7 + √3 + 4√2
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OpenStudy (anonymous):
yeah, i see why now
thanks
Mehek (mehek14):
yw :)
OpenStudy (anonymous):
and what about the other one?
Mehek (mehek14):
3√5 - 3√11 + 2√121 -3√90
we can simplify 2√121
and 3√90
list their factors
OpenStudy (anonymous):
18 * 5?
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OpenStudy (anonymous):
wait no
Mehek (mehek14):
no because 18 can be simplified more
OpenStudy (anonymous):
yeah, so 9 and 10
OpenStudy (anonymous):
and 121 is 1 * 121?
Mehek (mehek14):
right so
-3√90 = -3*3√10
-3 * 3 = -9
-9√10
and no 121 is a perfect square
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OpenStudy (anonymous):
ok, i knew it was a perfect square but i wasnt sure if i had to do anything to it.
Mehek (mehek14):
so 121 just becomes 11
and u had a 2 in front of it so 2 * 11 = ?
OpenStudy (anonymous):
2√11?
Mehek (mehek14):
nope
don't need √11 because perfect squares don't need to be radicals
it becomes just 11
OpenStudy (anonymous):
oh ok
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Mehek (mehek14):
so now multiply 11 * 2
OpenStudy (anonymous):
22
Mehek (mehek14):
so we have
3√5 - 3√11 + 22 -9√10
Mehek (mehek14):
that's all
OpenStudy (anonymous):
alright
thanks so much, and sorry for taking so long to understand
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Mehek (mehek14):
it's alright :)
OpenStudy (anonymous):
wait, so is that in rational exponent form?
OpenStudy (anonymous):
@Mehek14
Mehek (mehek14):
you didn't have any exponents tho o-0
OpenStudy (anonymous):
that's what my problem says, my teacher must of made a typo or something
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