Can someone check this proof for me? I think it is the first one. I need to find out:
CD = EF and AB = CE. Complete the statements to prove that AB = DF.

Question

Can someone check this proof for me? I think it is the first one. I need to find out:
CD = EF and AB = CE. Complete the statements to prove that AB = DF.

kitkat16 · Answer

attachment

kitkat16 · Answer

CD + DE = EF + DE by the (addition, subtraction, substitution, or transitive)

CE = DF by the (addition, subtraction, substitution, or transitive) Property of Equality.

CE = CD + DE and DF = EF + DE by (addition, subtraction, segment addition, or transitive)

Given, AB = CE and CE = DF implies AB = DF by the  (addition, subtraction, substitution, or transitive) Property of Equality.

kitkat16 · Answer

They all seem right to me but Im unsure of the terms. Help please

kitkat16 · Answer

@magepker728 can you help me please?

anonymous · Answer

let me think about this for a  mint

kitkat16 · Answer

ok thanks
I appreciate any help

anonymous · Answer

yeh im guessing first one too

kitkat16 · Answer

is it by (addition, subtraction, substitution, or transitive)? I'm confused by these terms

anonymous · Answer

u have to choose one of them?

kitkat16 · Answer

yes

anonymous · Answer

(addition, subtraction, substitution, or transitive)---> is the property

anonymous · Answer

u can the answer by doing each one of them

kitkat16 · Answer

Thats what i thought but I can only pick one

anonymous · Answer

addition property then

anonymous · Answer

lets say  this

anonymous · Answer

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