Two cars start from towns 440 miles apart and travel toward each other. they meet after 4 hr. find the speed of each car if one travels 10 mph faster than the other
Use the d=rt equation, where d = distance, r=rate, and t= time. That plus you know that their distance traveled in 4 hrs will sum up to 440 miles. this coupled with the fact that the rate of one car is 10 mph more than the other.
now use your algebra knowledge and solve the problem.
how would I set up the equation?
d = rt let r = the rate of the slower car in mph. Then the other car would be (r + 10) You have been given that t = 4 hrs. and d = 440 miles. Do I need to show you anything else?
turning what you said into an actual equation plz
440 = 4r + 4(r + 10) This is a procedure you must get to know, setting up the equation. Now just solve for r
Solve for r getting speed of slow car. Add 10 to r to get the speed of the faster car.
is it 440=4r+4r+40?
Yes, you are on track.
do the math.
440=8r+40?
still on track and closer to solution.
are you stuck?
yea I need the speed of both cars the slower and faster one. so I did 440=8r+40 and I am pretty sure I have to subtract 8 but where do I subtract 8 from
i mean subtract 40
The next step is to add the r's getting 4r+4r or 8r the next next step is to subtract 40 from both sides of the = sign this leaves you with 8r = 400 Finally divide both sides by 8 giving you the value of r These are using the rules of algebra.
Yes you are on track.!
What do you get for r What do you get for r + 10 ??
when i have 8r=400 i divided and got 50
Yes that is the value of r.........in miles per hour (mph) that was the speed of the slower car. Have you solved for the fast car?
no how do i solve for the fast car
Please read my previous posts, I have told you how to determine the speed of the faster car!!
In fact the problem tells you the speed of the faster car when you know the speed of the slower car.
wouldn't it be 60 mph faster car
Yes, great keep practicing the rules for algebra.
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