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What is the equation of the line that passes through the points (−2, 1) and (1, 10)? A: 3x-y=-7 B:3x-y=-5 C:3x-y=5 D:x+3y=-5
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you know how to find the slope?
yes m= y2-y1 / x2=x1
ok you need that first
i did that and i got 3
ok, next comes point slope formula
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i thought it was letter A but its negative not positive
let's pick \((1,10)\) so we start with \[y-y_1=m(x-x_1)\] or \[y-10=3(x-1)\]
multiply out get \[y-10=3x-3\] subtract \(3x\) from both sides i guess
i thought you would have to add 10 to 3?
sure you get \]-3x+y=7\]
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oops i meant \[-3x+y=7\]
but thats not one of the choices :(
course that is not one of your answer choices multiply both sides by \(-1\) get \[3x-7=-7\]
im confused
hello
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