IM BACK :)
Given 🔺ABC with a = 24, angle A = 108⁰ and angle B = 33⁰, find b. Round the sine value to the nearest thousandth and the answer to the nearest hundredth.

39.00

17.83

15.88

13.75

Question

IM BACK :)
Given 🔺ABC with a = 24, angle A = 108⁰ and angle B = 33⁰, find b. Round the sine value to the nearest thousandth and the answer to the nearest hundredth.

39.00

17.83

15.88

13.75

rhondasommer · Answer

|dw:1461252621496:dw|

rhondasommer · Answer

@sweetburger :) Sean can you help

sweetburger · Answer

This question we can use the law of sins.
$$\sin a /a = \sin b /b$$
So we can write this as

sweetburger · Answer

s$$\sin(108)/ 24 =\sin(33)/b$$

sweetburger · Answer

we can rewrite this to look like b *sin(108) = 24*sin(33)

sweetburger · Answer

divide both sides by sin(108) and you will have b by itself

rhondasommer · Answer

couldnt you just cross multiply?

sweetburger · Answer

Yes, that is what I did.

rhondasommer · Answer

so wouldnt we just simplify it?

rhondasommer · Answer

0.95*B=0.54*24
0.95*B=12.96
B=13.6

why would we divide both sides by sin(108)?

rhondasommer · Answer

whoops i messed up one sec

sweetburger · Answer

well the way you did it, it would be unecessary to divide both sides by sin(108) because instead you didvided both sides by .95

sweetburger · Answer

which is basically the same thing written 2 different ways

rhondasommer · Answer

0.951*B= 0.545*24
0.951*B=13.08
B=13.75

And oh i get it now :)

sweetburger · Answer

looks good gj @RhondaSommer

rhondasommer · Answer

ok so now i have to find c

rhondasommer · Answer

But ill just tag you again :)

sweetburger · Answer

ok