Question

a

Answer 1

is it \[6^{2x}+6^x-56=0\]

Answer 2

call \(y=6^x\) and solve the resulting quartic equation

Answer 3

u = 6^x

then yes

Answer 4

or use \(u\) if you like it better than \(y\)

Answer 5

no
the power rule is \[y^x = x \ln y\] you should drop down the power

Answer 6

6^x = 7

The next step is:

\(\Large x~ln 6= ln7\)

Answer 7

right so 6^x = 6ln then,

how is the 6 in the front if it is the x?

Answer 8

It is 6 raised to the power of x

\(\Large ln 6^x = x ln6\)

Answer 9

aaaaaaah ok

Answer 10

no 6^x isn't equal to 6 ln x
the exponent is x

Answer 11

the log rule:

\(\Large\bf log_b x^y = y\cdot log_b x\)