The perimeter of a rectangle is less than 70 ft. The length of the rectangle is 5 ft longer than its width. Write an equation representing the length (L = length) of the rectangle in terms of Its width. L = 5w b) The formula for perimeter of a rectangle is 2W + 2L = P W is the width, L is the length, and P is the perimeter. Write an inequality using the formula (plug in the value of L found in part a, the value of P, and replace the equal sign with the appropriate inequality symbol). c) Simplify the inequality to find width of the rectangle.
what class is this?
Algebra
1 or 2
1
ok
can you help??
yes
thanks
yup no problem
The length is 5 ft longer than the width --> L = W + 5 . . . that's one equation that describes length in terms of width. The perimeter is twice the length + twice the width --> 70 = 2L + 2W Subtracting 2W from both sides--> 70 - 2W = 2L Divide both sides by 2--> 35 - W = L . . . that's another equation that describes length in terms of width.
does that help any?
not really. i need to make an inequality
ok but you have to figure out the length and width before doing an inequality
do you go to flvs?
|dw:1461286160175:dw|
Join our real-time social learning platform and learn together with your friends!