Question

A man is on a diving board that is 50 feet above the ground. Suppose the man's starting upward velocity is 5 ft/s. Use 0 = -16t^2 + vt + c, where c is the starting height. Find the number of seconds t before he hits the water. Round to the nearest tenth of a second.

Answer 1

We have each variable we need

\[\large −16t^2+vt+c=0\]


Plugging in c = 15 and v = 5 we would have

\[\large −16t^2+5t+50=0\]


From there, we just solve the quadratic

Answer 2

@johnweldon1993 So I just solve -16t^2 + 5t + 50 = 0?

Answer 3

mmhmm :)

Answer 4

Ok thank you!

Answer 5

Not a problem!