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4d+1=√ 3
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d= −1−3√ / 4 o.m.g i can't put it, but4 is the denominator
you mean \(4d + 1 = \sqrt 3\) then what you got is not correct .
subtract 1 from both sides. \(4d = \sqrt 3 - 1\) then just divide both sides by 4
wait the square root of 3 divide by 1?
\(\Large \sqrt 3 - 1\) 1 subtracted from sqrt 3
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i got 2
\(4d = \sqrt 3 - 1 \\ \dfrac{4d}{4} =\dfrac{\sqrt 3 -1}{4} \\d= \dfrac{\sqrt 3 -1}{4} \)
you won't get an integer answer
\( \\d= \dfrac{\sqrt 3 -1}{4}\) is the final answer
Oh i actully did srt 3and one the wrong way x3 Thanks Hartn<3
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welcome ^_^
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