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Mathematics 19 Online
alones (alones):

4d+1=√ 3

alones (alones):

d= −1−3√ / 4 o.m.g i can't put it, but4 is the denominator

hartnn (hartnn):

you mean \(4d + 1 = \sqrt 3\) then what you got is not correct .

hartnn (hartnn):

subtract 1 from both sides. \(4d = \sqrt 3 - 1\) then just divide both sides by 4

alones (alones):

wait the square root of 3 divide by 1?

hartnn (hartnn):

\(\Large \sqrt 3 - 1\) 1 subtracted from sqrt 3

alones (alones):

i got 2

hartnn (hartnn):

\(4d = \sqrt 3 - 1 \\ \dfrac{4d}{4} =\dfrac{\sqrt 3 -1}{4} \\d= \dfrac{\sqrt 3 -1}{4} \)

hartnn (hartnn):

you won't get an integer answer

hartnn (hartnn):

\( \\d= \dfrac{\sqrt 3 -1}{4}\) is the final answer

alones (alones):

Oh i actully did srt 3and one the wrong way x3 Thanks Hartn<3

hartnn (hartnn):

welcome ^_^

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