Question

quick verification :

Answer 1

\[e ^{-j 25 (rads)}\]

i) 25 rads = 25* 180/pi = 1432.394 deg

ii) 360 * 3 = 1080 deg

iii) 1432.394 - 1080 = 356.394 deg

iv) 356.394 deg = -3.606 deg ?

There fore:\[e^{j25 rad} = e ^{j -3.606 \deg} \]

Is that correct ?

Answer 2

\[e ^{j -3.606} = 1 \angle -3.606 \deg\]

Answer 3

What are you supposed to prove ?

Answer 4

i'd divide 25 by \(\pi\) as many times as necessary to get it under \(2 \pi\)

...so that you can find a sensible complex number

Answer 5

analyzing .....

Answer 6

@IrishBoy123 I was able to see that 25 rads goes into 7*pi rads 1.1369 times

Answer 7

25 * 0.13682 = 3.4202 rads

Answer 8

not actually sure what you are trying to show but here are some more data points!

a https://www.wolframalpha.com/input/?i=25++rads

https://www.wolframalpha.com/input/?i=.1327+*+pi