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i got 68
did you forget to divide by 2 do the actual integral to get a good steer
ohh so 34?
this is what i did: 2(f(1)+f(2)+f(3)) = 2(15+12+7) = 68
why do you have the base length is 2?
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what happens when you divide the interval from x=0 to x=3 into 3 sub-intervals of equal length?
how long are each of the sub-intervals?
Δx=3−0/3=1 Δx(f(0)+f(1)+f(2)) 1(16+15+12)=43
yes that is an upper approximation to the area you could also get a lower approximation to the area if you used your earlier sum times 1 that is lower sum= 1(15+12+7) upper sum=1(16+15+12)
oh ok so it is 34 bc i need lower
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