Question

@mehek14 @sleepyjess

Answer 1

i have no idea how to use that graph
you are supposed to read it backwards, but it is very confusing
so lets just think
if \(y=1\) then \[2^{2y}=2^{2\times 1}=2^2=4\] so 1 is not quite big enuf

Answer 2

on the other hand it is pretty close, so probably one plus a little bit
i can show you how to solve this exactly (with a calculator) if you like

Answer 3

yes please.

Answer 4

\[2^{2y}=5\\
2y=\frac{\log(5)}{\log(2)}\\
y=\frac{\log(5)}{2\log(2)}\]

Answer 5

of course you need a calculator type in \[\log(5)\div \log(2)\div2\]

Answer 6

or just use this
http://www.wolframalpha.com/input/?i=log%285%29%2F%282log%282%29%29