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What is the solution to the equation 9^(x − 2) = 27? x = 2.5 x = 0.5 x = −0.5 x = 3.5
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@jim_thompson5910
use base three for both sides
since \(27=3^3\) and \(9=3^2\) you can write it as \[3^{2(x-2)}=3^3\]
You need to take the log of both sides give you \[\log_{9}27=x-2\] And then solve for x
now that the bases are the same, set \[2(x-3)=3\] and solve for \(x\)
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i get D
yeah D
mistake in the distributive law there
\[2(x-2)=3\\ 2x-4=3\] etc
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