Question

does anyones know how i can solve this
3x^2+10-8=0

Answer 1

3x^2 + 10 - 8 = 0
3x^2 + 2 = 0
3x^2 = -2

Is there any other information given?

Answer 2

no

Answer 3

i think u have to factorise

Answer 4

3x^2 + 10 - 8 = 0
3x^2 + 2 = 0
3x^2 = -2

\[x^2 = -\frac{ 2 }{ 3 }\]

Answer 5

What are the option given to you?

Answer 6

the answere in the book says x=-4 or x=2/3

Answer 7

I think you've missed something while copying the question...please post a screenshot of the original question.

Answer 8

Is this the original question:
\[3x^2 + 10x - 8 = 0?\

Answer 9

\[3x^2 + 10x - 8 = 0\]

Answer 10

Factorise it.

Answer 11

yes

Answer 12

Use this method.

3x^2 + 10x - 8 = 0

Split the middle sum such that it's sum is equal to the product of the first term and the last term.

i.e multiple 3x^2(the first digit ) with 8 (the second digit)

So,
3x^2 multiplied by 8 = ?

Answer 13

24

Answer 14

Yes.
3 into 8 is 24.

So 3x^2 into 8 = 24x^2,right?

So now split the middle digit(that is 10) such that these two number when multiplies give 24x^2 as the product.

Answer 15

5

Answer 16

no no no..

5 times 5 is 25.

Those two numbers are 6x and 4x.

Answer 17

oh ok

Answer 18

3x^2 + 10x - 8 =0

Will give
(x+4)(3x - 2) = 0

Answer 19

x is -4 or x is 2/3

Answer 20

oh omg thank u so much aaron!