Algebra
18 Online
OpenStudy (galacticplunder):
An expression is shown below:
2x3y + 18xy - 10x2y - 90y
Part A: Rewrite the expression so that the GCF is factored completely. (3 points)
Part B: Rewrite the expression completely factored. Show the steps of your work. (4 points)
Part C: If the two middle terms were switched so that the expression became 2x3y - 10x2y + 18xy - 90y, would the factored expression no longer be equivalent to your answer in part B? Explain your reasoning. (3 points)
10 years ago
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OpenStudy (galacticplunder):
@BPDlkeme234 @jigglypuff314 @DanJS @imammalik_806 @SolomonZelman
10 years ago
OpenStudy (galacticplunder):
@mathstudent55
10 years ago
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@sleepyjess
10 years ago
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@inkyvoyd
10 years ago
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@Haseeb96 @DullJackel09
10 years ago
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OpenStudy (galacticplunder):
@gabbyalicorn @Mchilds15 @mathstudent55
10 years ago
OpenStudy (gabbyalicorn):
I have no idea. Sorry! @rebeccaxhawaii
10 years ago
OpenStudy (galacticplunder):
@re314 @reemii @Raphandryu @jacobciezki @londoncat @lordhelix8th @pandaecat
10 years ago
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@Tiny_Tina @tazzwilliams @theghostlycreeper @IconForHire56 @Ashchu117 @adamlevine @ajolly @studio-games @DullJackel09 @KayHoo22 @londoncat
10 years ago
OpenStudy (galacticplunder):
@xxbatmanevoxx @chris215 @chasebraves @charliemath @bani_xoxo @mathstudent55
10 years ago
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OpenStudy (gniiij):
Hi i can help
10 years ago
OpenStudy (galacticplunder):
Ok!
10 years ago
OpenStudy (galacticplunder):
I have part a:
2x^3 y + 18 xy −10x^2 y−90y = 2y (x^3 − 5x^2 + 9x − 45)
10 years ago
OpenStudy (galacticplunder):
I think
10 years ago
OpenStudy (gniiij):
so now distribute that to check that
10 years ago
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OpenStudy (galacticplunder):
?
sorry I have no idea how to do this
10 years ago
OpenStudy (gniiij):
so when you distribute it should be\[2x^3y-10x^2y+18xy-90y\]
10 years ago
OpenStudy (gniiij):
does that match the original equation?
10 years ago
OpenStudy (gniiij):
looks like it does!
10 years ago
OpenStudy (galacticplunder):
Ok Cool thanks.
10 years ago
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OpenStudy (galacticplunder):
What about part b though? I don't know how to do that
10 years ago
OpenStudy (gniiij):
Now to factor that, you need to factor the x^3-5x^2+9x-45
10 years ago
OpenStudy (gniiij):
do you know how to factor?
10 years ago
OpenStudy (galacticplunder):
not really...
10 years ago
OpenStudy (gniiij):
okay so i can tell you
10 years ago
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OpenStudy (galacticplunder):
Ok
10 years ago
OpenStudy (gniiij):
so when you are factoring, you are basically trying to simplify an expression
10 years ago
OpenStudy (gniiij):
for example if you wanted to factor x^2+25 you would want to find the factors of x^2 and the factors of 25
10 years ago
OpenStudy (gniiij):
you will need to learn how this is used more in geometry
10 years ago
OpenStudy (gniiij):
so for this expression, you need to find the factors of each
10 years ago
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OpenStudy (gniiij):
when you are factoring, it is one of these things where is is a trial and error
10 years ago
OpenStudy (galacticplunder):
Ok.
10 years ago
OpenStudy (galacticplunder):
So how would I factor x^3-5x^2+9x-45 ?
10 years ago
OpenStudy (gniiij):
you want to find two expressions that when you FOIL them out, it becomes that expression
10 years ago
OpenStudy (gniiij):
do you know FOIL?
10 years ago
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OpenStudy (galacticplunder):
i think so...
10 years ago
OpenStudy (galacticplunder):
im not 100% sure how to do it
10 years ago
OpenStudy (gniiij):
ok for example, FOIL (x^2+9)(x-5)
10 years ago
OpenStudy (gniiij):
we can see then how much you know
10 years ago
OpenStudy (galacticplunder):
i think i know nothing! lol
10 years ago
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OpenStudy (gniiij):
10 years ago
OpenStudy (gniiij):
does that explain it sort of?
10 years ago
OpenStudy (gniiij):
that is the concept
10 years ago
OpenStudy (galacticplunder):
ok so First Outer Inner Last
10 years ago
OpenStudy (gniiij):
yes
10 years ago
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OpenStudy (galacticplunder):
So the First would be x^2 times x
10 years ago
OpenStudy (gniiij):
YES
10 years ago
OpenStudy (galacticplunder):
then x^2 times 5
10 years ago
OpenStudy (gniiij):
times negative 5
10 years ago
OpenStudy (gniiij):
remember the signs
10 years ago
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OpenStudy (gniiij):
\[(x^2+9)(x-5)= (x^2*x)-(5*x^2)+(9*x)-(9*5)\]
10 years ago
OpenStudy (gniiij):
That is what it looks like
10 years ago
OpenStudy (galacticplunder):
oh ok
10 years ago
OpenStudy (gniiij):
now multiply everything in parenthesis
10 years ago
OpenStudy (galacticplunder):
-10 + -8x^2 ? i dont know but i get the idea of it
10 years ago
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OpenStudy (gniiij):
No... so what is x^2*x
10 years ago
OpenStudy (galacticplunder):
x^3
10 years ago
OpenStudy (gniiij):
ok so the first part is x^3
10 years ago
OpenStudy (gniiij):
what is 5*x^2
10 years ago
OpenStudy (galacticplunder):
5x^2
10 years ago
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OpenStudy (galacticplunder):
What about part b though?
10 years ago
OpenStudy (gniiij):
I basically just factored it out for you already
10 years ago
OpenStudy (gniiij):
that expression factored out is (x^3 − 5x^2 + 9x − 45)
10 years ago
OpenStudy (gniiij):
so your part b would be 2y(x2+9)(x−5)
10 years ago
OpenStudy (galacticplunder):
Thanks!!! Can you help me with part c?
10 years ago
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OpenStudy (gniiij):
sure
10 years ago
OpenStudy (gniiij):
it is no because they when factored, they are the same regardless
10 years ago
OpenStudy (galacticplunder):
Thank you so much for your help!!!
10 years ago
OpenStudy (gniiij):
No Problemo
10 years ago