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OpenStudy (pphalke):
how do I graph
3x+15=0
let x equal to 0 right?
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OpenStudy (pphalke):
@bmk614 @563blackghost
OpenStudy (pphalke):
if I did that I get 3(0)+15=0
and get 0+15=0
then get 15
strangeee plz help
OpenStudy (pphalke):
@inkyvoyd @HyperPiper
OpenStudy (pphalke):
@ace-n-it @jaelenecastro1998
OpenStudy (bmk614):
No. You need to solve for x, so get it by itself on one side.
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OpenStudy (pphalke):
how do I do that?
OpenStudy (mykie):
Start by subtracting both side by 15
Then 3x = -15
divide both sides by 3
x = -5
OpenStudy (bmk614):
Subtract 15 from both sides
3x=-15
Then divide by 3
x=-5
OpenStudy (bmk614):
This is going to be a vertical line at x=-5, because no matter what value you have for y, x will be -5.
OpenStudy (pphalke):
so it would be (0,-5) first
then (-5,0)???
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OpenStudy (bmk614):
No. just a straight up and down line at (-5,0)
OpenStudy (mykie):
No idea where you're getting that information from.
But since the answer is x=-5
It'll be (-5,0)
OpenStudy (pphalke):
OpenStudy (bmk614):
at x=-5 put a straight up and down line.
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