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(binominal experiments and simulations) six coins are tossed. what is the probability that the following occurs? 1. 3 heads and 3 tails
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3 heads and three tails? formula would be \[\binom{6}{3}\left(\frac{1}{2}\right)^6\]
where \[\binom{6}{3}=\frac{6\times 5\times 4}{3\times 2}\]
Isn't formula P(r) = C(n,r) P^r q^n-r
\[C(n,r)= \binom{n}{r}\] \[C(n,r)p^rq^{n-r}\] \[C(6,3)\left(\frac{1}{2}\right)^3\left(\frac{1}{2}\right)^{6-3}\] \[=C(6,3)\left(\frac{1}{2}\right)^3\left(\frac{1}{2}\right)^{3}\] \[=C(6,3)\left(\frac{1}{2}\right)^{3+3}=C(6,3)\left(\frac{1}{2}\right)^{6}\] \[=\binom{6}{3}\left(\frac{1}{2}\right)^{6}\] which is what satellite73 said
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