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Mathematics 22 Online
OpenStudy (pphalke):

please help me will fan and medal

OpenStudy (pphalke):

OpenStudy (greatlife44):

well we know that we have 425 tickets sold total. a = activity tickets and c = card member tickets. I feel we can make two equations for this: the first one we know that a and c when added up must be 425 that's the number of tickets \[a + c = 425 \] in the second equation, we represent the price of tickets. 1.25a+2.25c = 634.50 we can solve for c or a in the first equation 425-c = a 1.25(425-c)+2.25c = 634.50 531.25-1.25c+2.25c = 634.50 531.25+c = 634.50 c = 103 a = ? so how would we find a

OpenStudy (pphalke):

it says 422 tickets

OpenStudy (pphalke):

@greatlife44 it says there were 422 tickets sold

OpenStudy (pphalke):

@greatlife44 would what you did be the same ? its 422 tickets

OpenStudy (greatlife44):

a+c = 422

OpenStudy (greatlife44):

c = 103 103+a = 422

OpenStudy (greatlife44):

a = activity tickets c = cardholder tickets

OpenStudy (pphalke):

a=319

OpenStudy (pphalke):

@greatlife44

OpenStudy (greatlife44):

yeah.

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