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OpenStudy (pphalke):
OpenStudy (greatlife44):
well we know that we have 425 tickets sold total. a = activity tickets and c = card member tickets.
I feel we can make two equations for this:
the first one we know that a and c when added up must be 425 that's the number of tickets
\[a + c = 425 \]
in the second equation, we represent the price of tickets.
1.25a+2.25c = 634.50
we can solve for c or a in the first equation 425-c = a
1.25(425-c)+2.25c = 634.50
531.25-1.25c+2.25c = 634.50
531.25+c = 634.50
c = 103
a = ?
so how would we find a
OpenStudy (pphalke):
it says 422 tickets
OpenStudy (pphalke):
@greatlife44 it says there were 422 tickets sold
OpenStudy (pphalke):
@greatlife44 would what you did be the same ? its 422 tickets
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OpenStudy (greatlife44):
a+c = 422
OpenStudy (greatlife44):
c = 103
103+a = 422
OpenStudy (greatlife44):
a = activity tickets
c = cardholder tickets
OpenStudy (pphalke):
a=319
OpenStudy (pphalke):
@greatlife44
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