plz help
@kyleighlauren357 @Directrix
@math&ing001
What have you done so far ?
i dont know how to change the a b in to x y
You don't have to, you have an a-axis and a b-axis Plot according to that, the a replaces y and the b replaces x.
a= 1/2b +2 a-4b = -5 okay, so think about the A as Y and the B as x. y= 1/2x +2 y -4x = -5 so for the second equation, you need to put it in y = mx+b form so add 4x on both sides. you should get y= 4x -5 so know you have both the equations: y = 4x -5 y = 1/2x + 2 now graph each equations
if ypu dont know about changing b into x and y, think about it like this: in the first equation it had a= in a normal equation, it has y= so you IN THIS CASE you can assume that a= y and so b would = x
this doesnt make sense this graph @math&ing001
Well that's only one equation of the system, you still need to plot the other one to solve the system.
move the upper point on the graph a little bit to the LEFT. To where it is on the line
this is through desmos
yeah, you still have to graph the second equation
The first graph is fine @kyleighlauren357
it should be at 1 on the x-axis tho, and she has it at like 1.25 her graphs count by halves @math&ing001
likethis
Yep, the point of intersection woulb be the solution to your system !
how would i do it on my homewoek graph?
oh snap. nevermind i was looking at a different graph.. my bad. i have too many tabs open lol @math&ing001
It's alright ;]
@pphalke You type in the coordinates of the intersection point
the red graph is confusing what do i do on my graph
@pphalke you draw the same graph like you did on desmos.
its confusing
Select two points randomly from the line and put them on the graph, then draw that passes through them. Example y=4x-5 If x=0 then y=-5 So (0,-5) could be the first point.
draw a line*
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