Question

WILL FAN AND MEDAL!!!!!! A metal worker has a metal alloy that is 20% copper and another alloy that is 60% copper. How many kilograms of each alloy should the metalworker combine to create 80 kg of a 52% copper alloy?

Answer 1

Take a look at this:
https://www.algebra.com/algebra/homework/word/mixtures/Mixture_Word_Problems.faq.question.900309.html
It may help you find your solution.

Answer 2

A = 20% copper alloy.
B = 60% copper alloy.

a + b = 80

a = (80-b)

So get 52% copper.

We multiply .52 by 80 that gives 41.6

So we may frame this equation:

.20a + .60b = .52(80)
.20a + .60b = 41.6

Now we substitute a = (80-b) in this equation.
.20(80-b) + .60b = 41.6
16 - .20b + .60b = 41.6
.40b = 41.6 - 16
b = 25.6/.4
b = 64 kg of 60% copper
:

Now can you calculate a?

To make it easier for you I'll do the first step i.e frame the frame equation.

Remember this:
a + b = 80

b = 64 kg of 60% copper(Calculated).

a + 64 = 80
a = 80-64
a= 16 kg of 20% copper.