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if it is a positive 4/3 on the graph how do u graph that? my y intercept is (0,-7)
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I dont understand your question . What is 4/3 - the slope of a line?
Mind ensuring that you have copied the problem down here exactly as presented to you?
if it is slope, it would be up 4 and over to the right 3. slope = rise over run 4=rise 3=run
ill copy the problem
|dw:1461966175621:dw|
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go up on the y axis 4, then go right 3
the line passes through where y = -7 and get the slope the way muscrat said
it is positive, so it will be slanted upwards. like i said earlier slope=rise over run
would it be (4,-3)?
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not quite.
3 to the right, then 4 up.( from the point (0,-7)
that is at 3 , (7-4) = (3,-3)
so it would be (0,-7) and (3,4)
|dw:1461966493173:dw|
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